Identity trigonometry. Show that: [tex]\displaystyle \sec x~(1+\sin x)=\frac{\sin x-\cos x+1}{\sin x+\cos x-1}[/tex]
Matematika
Anonyme
Pertanyaan
Identity trigonometry. Show that:
[tex]\displaystyle \sec x~(1+\sin x)=\frac{\sin x-\cos x+1}{\sin x+\cos x-1}[/tex]
[tex]\displaystyle \sec x~(1+\sin x)=\frac{\sin x-\cos x+1}{\sin x+\cos x-1}[/tex]