cos ²x + 3 sin x + 3=0 ,0 ≤ x ≤ 360°
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cos ²x + 3 sin x + 3=0 ,0 ≤ x ≤ 360°
1 Jawaban
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1. Jawaban ErikCatosLawijaya
Materi : Persamaan Trigonometri
Pembahasan :
Batas Interval 0 ≤ x ≤ 360°
Cos²x + 3Sin x + 3 = 0
1 - Sin²x + 3Sin x + 3 = 0
Sin²x - 3Sin x - 4 = 0
(Sin x - 4)(Sin x + 1) = 0
Sin x = -1
Sin x = Sin 270°
x = 270°
Hp : {270°}