Matematika

Pertanyaan

integral(x pangkat 2 - 1/x pangkat 3 + 4 akar x dx

1 Jawaban

  • (x² - 1/x³ + 4√x) dx
    (x² - x^-3 + 4x^½) dx
    = (1/(2+1))x^(2+1) - (1/(-3+1))x^(-3+1) + (4/(½+1))x^(½+1) + C
    = ⅓x³ - (-½)x^-2 + (4/(3/2))x^3/2 + C
    = ⅓x³ + ½x^-2 + (8/3)x^3/2 + C
    = ⅓x³ + (1/x²) + (8/3)x√x + C

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