Integral x (3x-4) 4 dx

^ tanda pangkat
misalkan 3x - 4 = u
3 dx = du
dx = du/3
3x - 4 = u
3x = u + 4
x = (u + 4)/3
ubah ke bentuk u yg x nya
= {(u+4)/3 u⁴} du/3
= (1/9) {(u + 4)u⁴} du
= (1/9) (u^5 + 4u⁴) du
integral kan
= (1/9) {(1/(5+1))u^(5+1) + (4/(4+1))u^(4+1)} + C
= (1/9){(1/6)u^6 + (4/5)u^5} + C
= (1/9)(1/30)(5u^6 + 24u^5) + C
= (1/270)(5u^6 + 24u^5) + C
= (1/270)(u^5(5u + 24)) + C
= (1/270)((3x-4)^5 (5(3x-4) + 24)) + C
= (1/270){(3x - 4)^5 (15x - 20 + 24)} + C
= (1/270)(3x - 4)^5 (15x + 4) + C