Fungsi F oleh f(x)=ax+b jika bayangan -3=15 dan bayangan 3=9 tentukan nilai dari f(-2)+f(2)

- f(x)=ax+b f(-3) = a(-3)+b -15 = a(-3)+b -15 = -3a+b - f(x)=ax+b f(3) = a(3)+b f(3) = 3a+b -3a+b= -15 3a+b = 9 (dikurang) -6a = -24 a = -24 : -6 a = 4 3a+b = 9 3(4)+b =9 12+b =9 b = 9-12 b = -3 f(x) = ax+b f(x) = 4x-3 f(-2) = 4(-2)-3 f(-2) = -8-3 f(-2) = -11 f(2) = 4(2)-3 f(2) = 8-3 f(2) = 5 Jadi, f(-2)+f(2) = -11 + 5 = -6