hitunglah (^3log 5)*(^25log27) plis bantuin aku

Logarithm.

³㏒ 5 (²⁵㏒ 27)
= ³㏒ 5 [^(5²) ㏒ 3³]
= ³㏒ 5 [3/2 ⁵㏒ 3]
= 3/2 ³㏒ 3
= 3/2 (1) = 1,5 ← Answer.

Remember:
^(dᵃ) ㏒ cᵇ = b/a ^d ㏒ c
ᵃ㏒ b ᵇ㏒ c = ᵃ㏒ c