Jika log 2 = a, log 3 = b, log 7 = c Nyatakan logaritma berikut dalam a,b,c.... Tolong di jawab iya kak!

log 14 = log(7 x 2) = log 7 + log 2 = c + a

log 42 = log (2 x 3 x 7) =  log 2 + log 3 + log 7 = a + b + c

log 24 = log (2 x 2 x 2 x 3 ) = log 2 + log 2 + log 2 + log 3 = 3 log 2 + log 3 = 3a + b

log 2/3 = log 2 - log 3 = a - b

log 2⁴ = log (2 x 2 x 2 x 2)= log 2 + log 2 + log 2 + log 2 = 4 log 2 = 4a

log √3 = log 3^0.5 = 0.5 log 3 = 1/2 log 3 = 1/2 b

log 1.5 = log (3/2) = log 3 - log 2 = b - a

log 5 = log (10/2) = log 10 - log 2 = 1 - a



maaf cuman bisa segitu