1)√48+5√2-√125+√50= 2)(2√2+√3)(√2-4√3)= 3)(7√3-5√2)(2√3+3√2=

Materi : Akar dan pangkat

Pembahasan :
1.

√48 + 5√2 - √125 + √50
= √(16.3) + 5√2 - √(25.5) + √(25.2)
= 4√3 + 5√2 - 5√5 + 5√2
= 4√3 - 5√5 + 10√2

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2.

(2√2 + √3)(√2 - 4√3)
= (2√2)(√2) - (2√2)(4√3) + (√3)(√2) - (√3)(4√3)
= 4 - 8√6 + √6 - 12
= -8 - 7√6

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3.

(7√3 - 5√2)(2√3 + 3√2)
= (7√3)(2√3) + (7√3)(3√2) - (5√2)(2√3) - (5√2)(3√2)
= 42 + 21√6 - 10√6 - 30
= 12√6 + 12