nilai dari 1/3+1/6+1/12+...1/192=

Barisan Geometri
1/3 + 1/6 + 1/12 + ... + 1/192
a = 1/3
r = U2/U1 = 1/6 / 1/3 = 1/2

Un = 1/192
ar^n = 1/192
1/3 (1/2)^n = 192
2^-n = 3/192
2^-n = 1/64
2^-n = 2^-6
n = 6

Sn = a(1 - r^n)/(1 - r)
S6 = (1/3)(1 - 1/64)/1/2
S6 = (2/3)(63/64)
S6 = 21/32