Nilai dari ²log 80 + ²log √6 + ²log√1/32 - ²log 5 adalah..

pakai persamaan logaritma yaa
berarti
²log(80√6×√1/32:5)
=²log(16√3:√16)
=²log(16√3:4)
=²log(4√3)
=²log4 + ²log√3
=2+²log√3

²log16 + ²log5 + ²log6½ + ²log32-¹ - ²log5 = ²log16 - ²log32 + ²log6½ =
4 - 5 + ²log6½ = - 1 + ²log 6½