Pliss bantuu...fastt! (3p^)^ + (4p^)^ --------------------- = 80 (3p)^ - (2p)^ Maka nilai p^ =? Keterangan: ^=kuadrat

(3p²)² + (4p²)²
--------------------- = 80
(3p)² - (2p)²

3².p^(2×2) + 4².p^(2×2)
--------------------------------- = 80
3².p² - 2².p²

9.p⁴ + 16.p⁴
----------------- = 80
9.p² - 4.p²

(9 + 16)p⁴
-------------- = 80
(9 - 4)p²

25p⁴
--------- = 80
5p²

(25/5)(p⁴/p²) = 80
5p² = 80
p² = 80/5
p² = 16
p = √16
p = 4 atau p = -4