A) |2x + 3| > |x + 1| = B) |x^2 - 5 | < 1 = C) |x -2|^2 + 3 < 4 |x - 2| = Cepat ya jawabnya. Please. Mksh

semoga membantu dan jangan lupa follow
kalau bisa jadikan jawaban terbaik☺

a. |2x + 3| > | x + 1 |
| 2x + 3 | - | x + 1 | > 0
2x + 3 - (x + 1) > 0,2x + 3 ≥ 0, x + 1 ≥0
-(2x + 3) - (x + 1) > 0, 2x + 3 < 0, x + 1 ≥ 0
2x + 3 - (-(x + 1) ) > 0, 2x + 3 ≥ 0, x + 1 < 0
- (2x + 3) - (-(x + 1) ) > 0,2x + 3 < 0, x + 1 < 0
x > -2 , x ≥ - 3/2, x ≥ - 1
x < - 4/3, x < - 3/2, x ≥ - 1
x > - 4/3, x ≥ - 3/2, x < - 1
x < - 2, x < - 3/2, x < - 1
x > - 2, x € [-1, + oo]
x < - 4/3, x € 0
x > - 4/3, x € [-3/2, -1]
x < -2, x € [ -oo, -3/2]
x € [-1, + oo]
x € 0
x € [-4/3, -1]
x € [oo, -2]
x € [ -oo, -2] U [-4/3, + oo]

No. B ada digambar

C. (x - 2)² + 3 < 4x - 8
(x - 2)² < 4x - 8 - 3
x² - 4x + 4 < 4x - 11
x² - 4x < 4x - 15
x² + 8x < -15
x² < - 15/8x
x < √-15/8x

(2x 13) > (x + 1)
2x > x + 1 - 3
2x - x > 2
x >- 2

x² - 5 < 1
x² < 6
x < √6