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jika rangkaian paralel R2=R3=10 ohm dan rangkaian seri R1=R4=12 ohm dan V=20 volt. berapakah kuat arus yg mengalir

1 Jawaban

  • 1/Rp = 1/R2 + 1/R3
    1/Rp = 1/10 + 1/10
    1/Rp = 2/10
    Rp = 10/2 = 5 ohm

    Rs = R1 + R4
    Rs = 12 ohm + 12 ohm = 24 ohm

    Rtotal = 5 + 24 = 29 ohm

    I = V/Rtotal
    I = 20/29
    I = 0,69 A

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